Nuprl Lemma : is_leaf_wf 4,23

E:Type, t:Tree(E). is_leaf(t)   
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Definitionsis_leaf(t), , Tree(E), x:A. B(x), tree_con(E;T), Case tree_leaf(x) => body(x) cont, Case(value) body, Default => body, {T}, true, t  T, false
Lemmasbfalse wf, btrue wf, tree wf

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